Question:-
A 230 volt, 50Hz one pulse SCR controlled convertor is triggered at a firing angle of 40°and load current extinguishes at an angle of 210°.

Calculate the average load current for R = 5 ohm & L = 2 mH
Option (A)
12.5 A
Option (B)
16.9 A
Option(C)
20.5 A
Option(D)
21.7 A
Correct Option:
(B)
Question Solution:
turn - off time (tc) = ((2π -β)/ω)
=((360-210) π)/(180 x 2π x 50 ))
Tc = 8.33 m sec
Average output voltage (v0)
V0 = (√2.230/π )(cos40° - cos210°)
= 84.477 volt
Average load current I0 =(v0/R)
I0 = (84.477/5) = 16.8954A
question-answer-faq-1636