The diode analysis so far has focused only on DC signals. We must also consider the application of diodes in circuits with time varying signals. This analysis is also complicated by the nonlinear nature of the diode. ts is often best left for
circuit simulation packages. Conversely, “small signal” analysis of nonlinear diode circuits can sometimes be done by hand. The concept behind small-signal operation is that a time varying signal with small amplitude “rides” on a DC value that may or may not be large.
The analysis of the circuit is then divided into two parts:
1. DC “bias” 2. AC “signal” of small amplitude. and the solutions are added together using superposition.
where vd(t) is some time varying waveform, perhaps periodic such as a sinusoid or triangle signal. The purpose of VD in this circuit is to set the operation of the diode about a point on the forward bias i-v characteristic curve of the diode. This is called the quiescent point, or Q point, and
the process of setting these DC values is called biasing the diode.
The total voltage at any time t is the sum of the DC and AC
provided the AC signal is small enough that the diode operates approximately in a linear fashion.
where ID is the DC diode current. We can series expand the exponential term using
and if vd(t) is small enough so that truncate
the series to two terms:
Substituting (3) in (2) gives
So, if vd(t) is small enough we can see from this last equation that iD is the sum (or superposition) of two components: DC and AC signals. What we’ve done is to linearize the problem by limiting the AC portion of vD to small values. The term T D nV I has units of ohms. It is called the diode smallsignal resistance:
From a physical viewpoint, rd is the inverse slope of the tangent line at a particular bias point along the haracteristic curve of the diode. Note that rd changes depending on the (DC) bias:
(Note that this rd is a fundamentally different quantity than rD used in the PWL model of the diode discussed in the previous lecture.) The equivalent circuit for the small-signal operation of diodes is:
Because we have linearized the operation of the diode (by
restricting the analysis to small AC signals), we can use
superposition to analyze the composite DC and AC signals.
That is, “signal analysis is performed by eliminating all DC
sources” (short out DC voltage sources/open circuit DC current sources) “and replacing the diode with its small-signal resistance rd.” This process is illustrated below:
Example N4.1 (Text example 3.6). For the circuit shown below, determine vD when
The diode specifications are
• 0.7-V drop at 1 mAdc
• n = 2.
As we discussed, for small AC signals we can separate the DC analysis from the AC (i.e., linearized). We need to start with the DC bias. Assuming 0.7 D V ˜ V for a silicon diode the DC current is
Since 1 D I ˜ mA, then VD will be very close to the assumed
value. At this DC bias, then the small-signal resistance at the Q point is
We use this rd as the equivalent resistance in the small-signal model of the diode
The AC voltage across the diode is found from voltage division as
The corresponding phasor diode voltage is then
where the subscript “p” indicates a peak value and the “pp”
subscript means a peak-to-peak value. Were we justified in using a small-signal assumption for this problem?
which is much less than 2. So, yes, the small-signal assumption is valid here. As an aside, note that in this circuit the ripple in the voltage has been reduced at the output. At the input, the ripple is 2/10=20% of the DC component while at the output the ripple is
0.0107/0.7=1.5% of the DC component.
See text example 3.7 for another example of this ripple
Diode High Frequency Model
This purely resistive AC model for the diode works well when the frequency of the AC signals is sufficiently low.
At high frequencies, we need to include the effects that arise due to these time varying signals and the charge separation that exists in the depletion region and in the bulk p and n regions of the diode under forward bias conditions.
Within the device and the depletion region there exists an
electric field, as discussed in Lecture 2. For AC signals, this electric field is varying with time. As you’ve learned in electromagnetics, a time varying electric field is a displacement current. The effects of a displacement
current are modeled by equivalent circuit capacitances:
We won’t do anything with this effect now. This is presented primarily as an FYI. (However, later in the course we will investigate this capacitive junction effect in transistors and how it affects the gain of transistor amplifier circuits at high