TEM TE and TM Modes for Waveguides Rectangular Waveguide
We will now generalize our discussion of transmission lines by
considering EM waveguides. These are “pipes” that guide EM
waves. Coaxial cables, hollow metal pipes, and fiber optical
cables are all examples of waveguides. We will assume that the waveguide is invariant in the zdirection:
and that the wave is propagating in z as e- jbz . (We could also have assumed propagation in –z.)
Types of EM Waves
We will first develop an extremely interesting property of EM
waves that propagate in homogeneous waveguides. This will
lead to the concept of “modes” and their classification as
• Transverse Electric and Magnetic (TEM),
• Transverse Electric (TE), or
• Transverse Magnetic (TM).
Proceeding from the Maxwell curl equations
However, the spatial variation in z is known so that
Consequently, these curl equations simplify to
We can perform a similar expansion of Ampère’s equation
Ñ * `H = jw e `E to obtain
Now, (1)-(6) can be manipulated to produce simple algebraic
equations for the transverse (x and y) components of `E and `H .
For example, from (1):
Substituting for `Ey from (5) we find
where kc2 = k2 - b 2 and k2 = w2me . Similarly, we can show that
Most important point: From (7)-(10), we can see that all
transverse components of `E and `H can be determined from
only the axial components ` Ez and ` Hz . It is this fact that allows
the mode designations TEM, TE, and TM.
Furthermore, we can use superposition to reduce the complexity
of the solution by considering each of these mode types
separately, then adding the fields together at the end.
TE Modes and Rectangular Waveguides
A transverse electric (TE) wave has Ez = 0 and Hz = 0. Consequently, all `E components are transverse to the direction of propagation. Hence, in (7)-(10) with Ez =0 , then all transverse components of `E and `H are known once we find a solution for only Hz . Neat!
For a rectangular waveguide, the solutions for Ex , Ey , Hx , Hy ,
and Hz are obtained in Section 3.3 of the text. The solution and the solution process are interesting, but not needed in this course. What is found in that section is that
These m and n indices indicate that only discrete solutions for
the transverse wavenumber (kc) are allowed. Physically, this occurs because we’ve bounded the system in the x and y directions. (A vaguely similar situation occurs in atoms, leading to shell orbitals.) Notice something important. From (11), we find that m = n = 0 means that , kc 00 = 0. In (7)-(10), this implies infinite field amplitudes, which is not a physical result. Consequently, the m = n = 0 TE or TM modes are not allowed. One exception might occur if Ez = Hz = 0since this leads to indeterminate forms in (7)-(10). However, it can be shown that inside hollow metallic waveguides when both m = n = 0 and Ez = Hz = 0, then `E = `H = 0. This means there is no TEM mode.
Consequently, EM waves will propagate only when the frequency is “large enough” since there is no TEM mode.
Otherwise b will be imaginary (b ® - ja ), leading to pure
attenuation and no propagation of the wave e? j` z ®e -az . This turns out to be a general result. That is, for a hollow conductor, EM waves will propagate only when the frequency is large enough and exceeds some lower threshold.
It can be shown that guided EM waves require at least two
conductors in order to support wave propagation all the way to
0+ Hz. This minimum propagation frequency is called the cutoff
frequency f . The cutoff frequencies for TE modes in a rectangular waveguide are determined from (12) with b = 0 to be
In other words, these are the frequencies where b mn = 0 andwave propagation begins when the frequency slightly exceeds fcmn .
For an X-band rectangular waveguide, the cross-sectional
dimensions are a = 2.286 cm and b = 1.016 cm. Using (13):
TEm,n Mode Cutoff Frequencies
In the X-band region (? 8.2-12.5 GHz), only the TE10 mode can propagate in the waveguide regardless of how it is excited. (We’ll also see shortly that no TM modes will propagate either.) This is called single mode operation and is most often the preferred application for hollow waveguides.
On the other hand, at 15.5 GHz any combination of the first
three of these modes could exist and propagate inside a metal,
rectangular waveguide. Which combination actually exists will
depend on how the waveguide is excited. Note that the TE11 mode (and all higher-ordered TE modes) could not propagate. (We’ll also see next that no TM modes will propagate at 15.5 GHz either.)
TM Modes and Rectangular Waveguides
Conversely to TE modes, transverse magnetic (TM) modes have
Hz = 0 and Ez ¹ 0
The expression for the cutoff frequencies of TM modes in a
is very similar to that for TE modes given in (13).
It can be shown that if either m = 0 or n = 0 for TM modes,
then `E = `H = 0. This means that no TM modes with m = 0 or
n = 0 are allowable in a rectangular waveguide. For an X-band waveguide:
TMm,n Mode Cutoff Frequencies
Therefore, no TM modes can propagate in an X-band
rectangular waveguide when f < 16.156 GHz.
Note that from 6.56 GHz £ f £ 13.12 GHz in the X-band
rectangular waveguide, only the TE10 mode can propagate. This
mode is called the dominant mode of the waveguide.
See Fig 3.9 in the text for plots of the electric and magnetic
fields associated with this mode.
The transverse electric and magnetic (TEM) modes are
characterized by `Ez = 0 and `Hz = 0. In order for this to occur, it can be shown from (3.4) and (3.5)
that it is necessary for fc = 0 . In other words, there is no cutoff frequency for waveguides that support TEM waves. Rectangular, circular, elliptical, and all hollow, metallic
waveguides cannot support TEM waves. It can be shown that at least two separate conductors are required for TEM waves. Examples of waveguides that will allow TEM modes include coaxial cable, parallel plate waveguide, stripline, and microstrip.
Microstrip is the type of microwave circuit interconnection that
we will use in this course. This “waveguide” will support the
“quasi-TEM” mode, which like regular TEM modes has no nonzero cutoff frequency. However, if the frequency is large enough, other modes will begin to propagate on a microstrip. This is usually not a desirable situation.