AIEEE Mock Test 2

AIEEE Mock Test 2
Question:-
Option (A)
zero Joule
Option (B)
2 x 10-3 J
Option (C)
4 x 10-3 J
Option (D)
1 x 10-3 J
Correct Option:
B
Question Solution:
heat =(1/2) CV2
Heat = (1/2) x 20 x 10-6 x 100 = 10-3 Joule
Question:-
Option (A)
19 g
Option (B)
91 g
Option (C)
17 g
Option (D)
26 g
Correct Option:
A
Question Solution:
P = 100 watt
V = 110 volt
Time = 10 hrs = 10 x 60 x 60 = 3.6 x 104 sec
P = V x I
P    100
i = --- = ----
V    110
Eit
W = Zit = ----
96500
112    100    3.6 x 104
= ----- x --- x -------
2      110      96500

= 19.05 gm
Approx = 19 gm
Question:-
Option (A)
Internal resistance of battery is 10 ohm
Option (B)
e.m.f. of battery is 20 V
Option (C)
maximum current drawn is 2A
Option (D)
All of the above
Correct Option:
D
Question Solution:
E
V = ---
R+r

Used V= IR
E
I= ----
R+r

Question:-
Option (A)
1 sec
Option (B)
2 sec
Option (C)
3 sec
Option (D)
6 sec
Correct Option:
B
Question Solution:
y=A sin wt
When P.E. is 75%, K.E. = 25%

Ö3
---A= A sin wt ; 25% is P.E.
2
Sin wt = (p/3)
2p
--- x t = (p/3)
12
t = 2 sec
Question:-
Option (A)
3.3 x 10-18 C
Option (B)
3.2 x 10-18 C
Option (C)
1.6 x 10-18 C
Option (D)
4.8 x 10-18 C
Correct Option:
A
Question Solution:
In steady state, Electric force on drop = weight of drop \ qE = mg Þq = (mg/E)   9.9 x 10-15 x 10 = ----------------      3 x 104 = 3.3 x 10-18C
Question:-
Option (A)
m0 / pr
Option (B)
zero
Option (C)
2.5m0 / p r
Option (D)
5r
Correct Option:
B
Question Solution:
Net ‘B’ is zero, using ampere critical law.