AIEEE old paper set 2

AIEEE old paper set 2
Question:-
Option (A)
0.27 A P2 to P1
Option (B)
0.03 A P1 to P2
Option (C)
0.03 A P2 to P1
Option (D)
0.27 A P1 to P2
Correct Option:
C
Question Solution:

Vp2 - Vp1 ={(5/2)+(0/10) – (2/1)} /{ (1/2) + (1/10) + 1/1) }
I= ((Vp2-Vp2)/10) = 0.03 from P2 → P1
Question:-
Option (A)
2
Option (B)
-1
Option (C)
0
Option (D)
1
Correct Option:
D
Question Solution:
The system of equations x – cy – bz = 0, cx – y + az = 0 and bx + ay – z = 0 have non-trivial solution if




Þ 1(1 – a2) + c(–c – ab) – b(ca + b) = 0
Þ a2 + b2 + c2 + 2abc = 1.
Question:-
Option (A)
If detA = ± 1, then A–1 exists but all its entries are not necessarily integers
Option (B)
If detA ≠ ± 1, then A–1 exists and all its entries are non-integers
Option (C)
If detA = ± 1, then A–1 exists and all its entries are integers
Option (D)
If detA = ± 1, then A–1 need not exist
Correct Option:
C
Question Solution:
Each entry of A is integer, so the cofactor of every entry is an integer and hence each entry in the
adjoint of matrix A is integer.

Now detA = ± 1 and A-1 = 1/det(A)(adj A)

Þ all entries in A-1 are integers.
Question:-
Option (A)
0.16 J
Option (B)
1.00 J
Option (C)
0.67 J
Option (D)
0.34 J
Correct Option:
C
Question Solution:
M1u1 + m2u2 = (m1 + m2)v
v = 2/3 m/s
Energy loss = (1/2 ) (0.5 ) x (2)2 - (1/2) (1.5) x (2/3)2 =067J