Question:-
Atmospheric air at dry bulb temperature of 15°C enters a heating coil whose surface temperature is maintained at 40°C. The air leaves the heating coil at 25°C. What will be the by-pass factor of the heating coil?
Option (A)
0.376
Option (B)
0.4
Option(C)
0.6
Option(D)
0.67
Correct Option:
(C)
Question Solution:
By pass factor = {(t3-t2)/(t3-t1)}
Where, t3 = temperature of heating coil = 40°C
t2 = exit temperature of air = 25°C
t1 = temperature of air at inlet = 15°C
BPF = {(40-25)/(40-15)} = 0.6
question-answer-faq-9468