CAT Old Paper - Analytical Reasoning

CAT Old Paper - Analytical Reasoning
Question:-
Option (A)
2,5,3,2
Option (B)
0,5,3,1
Option (C)
1,5,3,2
Option (D)
2,3,5,1
Option (E)
1,3,5,1
Correct Option:
B
Question Solution:
It is given in the question that path BC is under repair, hence available paths to reach from S to T are SBAT, SAT, SDCT and SDT. Now using options, we find that option (b) gives the same cost of travel from S to T.
A = 0, B = 5, C = 3, D = 1
SBAT = 2 + 5 + 2 + 0 + 5 = Rs 14
SAT = 9 + 0 + 5 = Rs 14
SDCT = 7 + 1 + 1 + 3 + 2 = Rs 14
SDT = 7 + 1 + 6 = Rs 14
Question:-
Option (A)
0,5,4,1
Option (B)
0,5,2,2
Option (C)
1,5,3,3
Option (D)
1,5,3,2
Option (E)
0,4,3,2
Correct Option:
D
Question Solution:
Traffic among the different paths will be evenly distributed if the cost of travel (fuel cost plus toll charges) is same through all the given routes. Option (d) gives the cost of travel through all the routes as same.
A = 1, B = 5, C = 3, D = 2
S -> : SAT = 9+1+5 = Rs 15
S -> B : SBAT = 2+5+2+1+5 = Rs 15
SBCT = 2+5+3+3+2 = Rs 15
S -> D : SDCT = 7+2+1+3+2 = Rs 15
SDT = 7+2+6 = Rs 15
Question:-
Option (A)
1,5,3,3
Option (B)
1,4,43
Option (C)
1,5,4,2
Option (D)
0,5,2,3
Option (E)
0,5,2,2
Correct Option:
E
Question Solution:
Traffic from D to T is restricted hence available routes through A and C are SAT, SBAT, SBCT, SDCT. Option (e) given the same cost of travel.
SAT = 9+0+5 = Rs 14
SBAT = 2+5+2+0+5 = Rs 14
SBCT = 2+5+3+2+2 = Rs 14
SDCT = 7+2+1+2+2 = Rs 14
Question:-
Option (A)
0,52,2
Option (B)
0,5,4,1
Option (C)
1,5,3,3
Option (D)
1,5,3,2
Option (E)
1,5,4,2
Correct Option:
D
Question Solution:
For option (d) we have
A = 1, B = 5, C = 3, D = 2
SAT = 9+1+5 = Rs 15
SBAT = 2+5+2+1+5 = Rs 15
SDT = 7+2+6 = Rs 15
SDCT = 7+2+1+3+2 = Rs 15
SBCT = 2+5+3+3+2 = Rs 15
Question:-
Option (A)
Rs 7
Option (B)
Rs 9
Option (C)
Rs 10
Option (D)
Rs 13
Option (E)
Rs 14
Correct Option:
C
Question Solution:
Option (a) is ruled out because cost incurred from S to T will be Rs 7 only through SBCT assuming toll charges as B = 0 and C = 0, but in this case all traffic will be move through junction B.
Option (b) is ruled out because cost incurred from S to T will be Rs 9 when toll at B = 0 and C = 2. In this case also all traffic will be diverted though junction B.
Using option (c) we find that if toll charges at B = 3 and C = 0, then travel cost from S to through B will be Rs 10.
SBCT = 2+3+3+0+2 = Rs 10
and the same cost will be incurred through
SDCT = 7+0+1+0+2 = Rs 10
Since Rs 10 is the least hence option (d) and (e) are ruled out.