# Civil engineering Questions and solutions set - 1

Civil engineering Questions and solutions set - 1
Question:-
Option (A)
2 h
Option (B)
4 h
Option (C)
6 h
Option (D)
8 h
Correct Option:
D
Question Solution:
(F/M)ratio = (Q.S / 1000V.Xss) = 1
Þ 0.22 = (28 x 106 x 220) / (1000 x 3000V)
V = 9333.33m3
\HRT = (V/Q) x 24= 8 hour
Where Q = 2800 × 103 l/d
Si = influent BOD
= 220 mg/L
Xss= MLSS
= 3000 mg/L
V= Volume (m3)
Question:-
Option (A)
0.97m
Option (B)
9.70m
Option (C)
10.34m
Option (D)
10.97m
Correct Option:
C
Question Solution:
Shrinkage factor = (Shrunk scale / Original scale) = (14.5/15)
Shrunk RF = Original RF + Shrinkage factor
= (1/1000) x (14.5/15) = 1/1034.48
\ Shrunk scale,
1cm = 1034.48/100
= 10.34m
Question:-
Option (A)
300mm
Option (B)
400mm
Option (C)
600mm
Option (D)
800mm
Correct Option:
C
Question Solution:
(Pu/fckbd) =(640 x 103) / (20 x 400 x 400) = 0.2
For (Pu/fckbd) = 0.2,
We have (Mu/fckbd) = 0.3 from the interaction diagram.
\ Mu = 0.3 × 20 × 400 × 4002 ×10-3
Þ Mu = 384000 kN-mm
But maximum uniaxial eccentricity is given by
e = (Mu/Pu)
= (384000/640) = 600mm
Question:-
Option (A)
1986 kW
Option (B)
1776 kW
Option (C)
1421 kW
Option (D)
1000 kW
Correct Option:
C
Question Solution:
P = hgQH = 0.9 x 9810 x 9 x 25 x 10-3 = 1986.525 kW
(P1/P2) = (H1/H2)3/2
Þ (1986.525 / P2) = (25/20)3/2
Þ P2 = 1421 kW
Question:-
Option (A)
17.5 kN
Option (B)
12.5 kN
Option (C)
8 kN
Option (D)
10 kN
Correct Option:
D
Question Solution:
PSteel £ {140 x 500) / (6 x 103)} = 11.67 kN
PAluminium £ {(90 x 400) / (2 x 103)} = 18 kN
PBronze £ {(100 x 200) / (2 x 103)} = 10 kN
\ Maximum value of P is 10 kN.
Question:-
Option (A)
115cm
Option (B)
12cm
Option (C)
227cm
Option (D)
250cm
Correct Option:
C
Question Solution:
Discharge at field
= water conveyance efficiency x discharge at minor
= 0.7 x 10 x 10-3m3/s
Duty of field = (Area/Discharge) = (2.4/(7x10-3))= 342.85 Ha/cumec
Delta = (864B/D) = ((864 x 90) / 342.85)= 226.8cm