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Analog and digital circuits

CSE - Analog and digital circuits - Questions and solutions
Question:-
Option (A)
Are high; and G1, G2 are low
Option (B)
Are high; and G1 is low, G2 is high
Option (C)
Are high; and G1, G2 are high
Option (D)
Are high; and G1 is high, G2 is low
Correct Option:
B
Question Solution:
Outputs are active low, so all the output lines of the chip will be high, when chip will be disabled i.e., G1 = 0 and `G2 = 1
Question:-
Option (A)
20 MHz
Option (B)
10 MHz
Option (C)
8 MHz
Option (D)
5 MHz
Correct Option:
D
Question Solution:
Maximum clock frequency = (1/(4 x 50 x 10-9)) = 5 MHz
Question:-
Option (A)
120
Option (B)
150
Option (C)
165
Option (D)
166
Correct Option:
C
Question Solution:
IE = (b+1)IB
IE = ((10-1.7)/5) = 1.66 mA
IB = (1/100) = 0.01mA
\ b+1 = 166 Þ b = 165
Question:-
Option (A)
3Vs1 - 6Vs2
Option (B)
2Vs1 - 3Vs2
Option (C)
2Vs1 - 2Vs2
Option (D)
3Vs1 - 2Vs2
Correct Option:
D
Question Solution:
Using superposition
For Vsi, V01 = {1+(2R/R)}Vs1
For Vs2, V02 = - (2R/R) Vs2
\ V00102 = 3Vs1 -2Vs2
Question:-
Option (A)
NHH = 2.4 V, NML = 1.8 V
Option (B)
NHH/sub> = 1.8 V, NML = 1.3 V
Option (C)
NHH = 0.7 V, NML = 1.8V
Option (D)
NMH = 0.7 V, NML = 1.3 V
Correct Option:
D
Question Solution:
NHH = {VOH(min) ~ VIH(min)} and
NHL = {VOL(max) ~ VIL(max)}
Question:-
Option (A)
(Xp.Xp+1. ------. Xq-1.Xq).(Xq+1 + Xq+2 + ----- + Xm-1)
Option (B)
(Xp Å Xp+1 Å ----- Xq).(`Xq+1 + `Xq+2 + ----- + `Xm-1)
Option (C)
(Xp + Xp+1 + ----- + Xq + Xq).(`Xq+1. -------.`Xm-1)
Option (D)
(X0 + X1 + X2 + ---- + Xq).(`Xq+1.`Xq+2.-----.`Xm-1)
Correct Option:
C