Question:-
A cube at high temperature is immersed in a constant temperature bath. It loses heat from its top bottom and side surface with heat transfer coefficient of h1, h2 and h3 respectively. The average heat transfer coefficient for the cube is
Option (A)
h1 + h2 + h3
Option (B)
(h1h2h3)1/3
Option(C)
(1/h1) + (1/h2) – (1/h3)
Option(D)
None of these
Correct Option:
(D)
Question Solution:
Q = (h1AΔT + h2AΔT + h34AΔT)
Q = hav x 6.A.ΔT.
\ hav = ((h1+h2+4h3)/6)
question-answer-faq-3059