Question:-
A 4-stroke diesel engine, when running at 2000 rpm has an injection duration of 1.5 ms. What is the corresponding duration of the crank angle in degrees?
Option (A)
18°
Option (B)
Option(C)
36°
Option(D)
15°
Correct Option:
(A)
Question Solution:
Time for injection = (q/360) x (60/N)
(N will be same for 2 or 4 stroke)
0.0015 = (q/360) x (60/2000)
q = (0.0015 x 360 x 2000) / 60 = 18°
question-answer-faq-9206