Categories

Electrical Engineering Questions and Solutions Set 2

Electrical Engineering Questions and Solutions Set 2
Question:-
Option (A)
2.25 rad/sec
Option (B)
22.54 rad/sec
Option (C)
0.225 rad/sec
Option (D)
225.43 rad/sec
Correct Option:
D
Question Solution:
f=25 Hz
=> ω=2πf = 157 rad/sec
tan φ=
=> tan 45°=
=> 1 - ω2 LC=RωC
=> 1 - (157)2 x 60 x 10-3 x C = 10 x 157 x C
=> C=328 μF
The resonant frequency = ωo =
=
=225.43 rad/sec
Question:-
Option (A)
3 A
Option (B)
3.8 A
Option (C)
4 A
Option (D)
1.8 A
Correct Option:
A
Question Solution:
at t = 0-, voltage across capacitor (open circuit)
vc(0-)=6 V
at t = 0+,
vc(0+)=vc(0-) = 6 V

Applying superposition,
Current due to current source, when voltage source is short-circuit
I1=
Current due to voltage source, when current source is open circuit,
I2=2 A
Total current=I1 + I2 = 1 + 2 = 3 A
Question:-
Option (A)
150 V
Option (B)
300 V
Option (C)
450 V
Option (D)
600 V
Correct Option:
B
Question Solution:
Vx-n=
{as the coils are electrically in series, hence, the same current i pass through the coils, M12 is negative}
Vx-n=
Similarly
Vy-n=
=
Vx-y=Vx-n + Vy-n
=
= 300 V