Electrical Engineering Questions and Solutions Set 6
Electrical Engineering Questions and Solutions Set 6
Question:-
Option (A)
(2, 1, 1, 1)
Option (B)
(1, -1, -1, 2)
Option (C)
(1, 1, 1, 2)
Option (D)
(2, -1, -1, 1)
Correct Option:
B
Question Solution:
Y_{11} = 2, Y_{12} = 1, Y_{21} = 1, Y_{22} = 1ÑY = 1, Z_{11} = 1/1 = 1, Z_{12} = - 1/1 = 1, Z_{21} = - 1/1
Question:-
Option (A)
54 Amp
Option (B)
25Amp
Option (C)
12 Amp
Option (D)
31.1Amp
Correct Option:
B
Question Solution:
DC level of output voltage will be 540.2 volt since the value of diode current is
high so high output Dc current may be assume constant. And DC value of current will be 54.02 Amp and RMS value of current will be 25.4 Amp
Question:-
Option (A)
3.5mWb
Option (B)
1.2mWb
Option (C)
14mWb
Option (D)
21mWb
Correct Option:
B
Question Solution:
E=357 volt = j.51.20.8500.4/60.2 so flux will be 1.2 mwb
Question:-
Option (A)
1500
Option (B)
1800
Option (C)
3000
Option (D)
3600
Correct Option:
A
Question Solution:
RPM of shaft=(P/T)x60 Here P=3000 T=120
Question:-
Option (A)
1kW/km per phase
Option (B)
0.83kw/km per phase
Option (C)
1.2 kW/km per phase
Option (D)
1.13 kW/km per phase
Correct Option:
D
Question Solution:
The corona loss is proportional to f+25 where f is in Hz
Question:-
Option (A)
625 W
Option (B)
600 W
Option (C)
650 W
Option (D)
700W
Correct Option:
A
Question Solution:
Copper loss= (Slip. Output power)/(1-slip) Cu loss= (0.04).15000/0.96=625 W