ECE - Questions and solutions set-14

Electronics and communication Engineering Questions and solutions set-14
Question:-
Option (A)
        1.6 μs
Option (B)
        3.2 μs
Option (C)
        6.4 μs
Option (D)
        12.8 μs
Correct Option:
B
Question Solution:
1 word = 16 bits
        To load 1 word -> 1 clock pulse is required
        To load 16 words -> 16 clock pulses will be req.
        Frequency = 5 MHz
        T = = 0.2 μ sec
        Total time req= 0.2 x 16 = 3.2 μ sec
Question:-
Option (A)
        (a.)
Option (B)
        (b.)
Option (C)
        (c.)
Option (D)
        (d.)
Correct Option:
D
Question Solution:
.Zin =
         =
        |Zin| =
        |Zin|ω = 2 =
Question:-
Option (A)
        
Option (B)
        
Option (C)
        
Option (D)
        
Correct Option:
D
Question Solution:
Lety = ... (i)
        We know
         = tan-1A - tan-1B... (ii)
        eqn (i) can be rearranged as in eqn (ii)
        y = = tan-1(x1/3) - tan-1(x1/2)
        Also, so,
        
Question:-
Option (A)
        

Option (B)
        

Option (C)
        

Option (D)
        

Correct Option:
D
Question Solution:
Since
        therefore,
        =>
        =>