ECE - Questions and solutions set-16

Electronics and communication Engineering Questions and solutions set-16
Question:-
Option (A)
1 MHz
Option (B)
1.2 MHz
Option (C)
4 MHz
Option (D)
2.6 MHz
Correct Option:
A
Question Solution:
Δf=100 kHz,
fc=20 MHz >> fm
For sinusoidal modulation
FM=
So this is a case of NBFM signal ;
hence
bandwidth=2fm = 2 x 500 kHz
=1000 kHz = 1 MHz
Question:-
Option (A)
192 A/m2
Option (B)
327 A/cm2
Option (C)
168 A/m2
Option (D)
192 A/cm2
Correct Option:
D
Question Solution:
J = σE = 12 x 16 = 192 A/cm2
Question:-
Option (A)
1.6
Option (B)
250
Option (C)
160
Option (D)
1600
Correct Option:
D
Question Solution:
Resonant frequency
ωr=
=25 k rad/sec
So Q =
=1600
Question:-
Option (A)
CY = 0
Option (B)
CY = 1
Option (C)
Either 0 or 1
Option (D)
None of these
Correct Option:
B
Question Solution:
XRA A -> CY = 0 and A = 00H
LXI B, 2051H -> B = 20H, C = 51H
PUSH B

POP PSW -> A = 20H ;  F = 51H

So CY = 1