Question:-
An enclosure consists of four surfaces 1, 2 3 and 4. The view factor for radiation heat transfer (Where the subscripts 1, 2, 3, 4 refer to the respective surface) are F11 = 0.1, F12 = 0.4 and F13 = 0.25. the surface areas A1 and A4 are 4 m2 and 2m2 respectively. The view factor F41 is
Option (A)
0.75
Option (B)
0.50
Option(C)
0.25
Option(D)
0.10
Correct Option:
(B)
Question Solution:
Surface enclosure theorem
F11 + F12 + F13 + F14 = 0
F14 = 1-(0.10 + 0.040 + 0.25)
F14 = 0.25 A1F14 = A4F41
F41 = 0.25 x 4/2 = 0.50
question-answer-faq-6091