Question:-
The data given in the table refers to an engine based on Carnot cycle,
where Q1 = Heat received (kJ/min)
Q2 = Heat rejected (kJ/s)
W = Work output (kW)




S.No. Q1 Q2 W
1. 1500 16.80 8.20
2. 1600 17.92 8.75
3. 1700 19.03 9.30
4. 1800 20.15 9.85

If heat received output will be, nearly by the engine is 2000 kJ/minute the work
Option (A)
9.98
Option (B)
10.39
Option(C)
11.54
Option(D)
10.95
Correct Option:
(D)
Question Solution:





S.NO. Q1(kj/min) Q2(kj/s) W(kw) h(%)
1. 1500 16.8 8.2 32.8
2. 1600 17.92 8.75 32.8
3. 1700 19.03 9.30 32.8
4. 1800 20.15 9.05 32.8
5. - - 32.8


W = Q1 - Q2
n = (W/Q1)
328 = [W /{(2000/6)(kj/s)}]
W = 10.93 kw.
question-answer-faq-6128