Question:-
An engine produces 10 kW break power while working with a brake thermal efficiency of 30%. If the calorific value of the fuel used is 40,000 kJ/kg, then what is the fuel consumption?
Option (A)
1.5 kg/hour
Option (B)
3.0 kg/hour
Option(C)
0.3. kg/hour
Option(D)
1.0 kg/hour
Correct Option:
(B)
Question Solution:
hbth = (B.P/mfcv)
0.30 = {10KJ/s / mf(40000(KJ/kg)}
mf = 8.33 x 10-4 (kg/sec)
mf = 8.33 x 10-4 x 3600 (Kg/hr)
mf = 3 Kg/hr.
question-answer-faq-9494