Question:-
For the epicyclic gear arrangement shown in the figure, w2 = 100rad / s clockwise (CW) and warm = 80rad / s counter clockwise (CCW).
The angular velocity w5(in rad/s) is

Option (A)
0
Option (B)
70CW
Option(C)
140CCW
Option(D)
140CW
Correct Option:
(C)
Question Solution:





Condition Arm/a 2 3/4 5
Arm fixed
2-rotates
+1rev
0 1 -(20/26)=5/6 -(20/26)x(32/80) = -1/3
Arm fixed
2-rotates
+x rev
0 x -(5/6)x -(x/3)
Add y y x+y -(5/6)x+y -(x/3) + y

Given warm = - 80rad/sec = y

w2 = 100 rad/sec = x+y

\ x+y = 100 Þ x = 100+80=180

w5 = -80(-180/3) = 140CCW
question-answer-faq-2368