Question:-
If diameter of long column is reduced by 20%, the percentage of reduction in Euler bucking load is
Option (A)
4
Option (B)
36
Option(C)
49
Option(D)
59
Correct Option:
(B)
Question Solution:
PE a d2
PE1 = Kd21
PE2 = Kd22
= K(0.8d1)2 = 0.64 kd21
(DPE / PE1) = {(PE1 - PE2) / PE1}
= {(Kd21 - 0.64Kd21) / Kd21} x 100
(DPE / PE1) x 100 = 36%
question-answer-faq-9337