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Fluid Mechanics and Fluid Machinery part -1

Fluid Mechanics and Fluid Machinery part -1
Question:-
Option (A)
Fully open
Option (B)
Fully closed
Option (C)
Partially open
Option (D)
50% open
Correct Option:
B
Question Solution:
A centrifugal pump can be started with its delivery value fully closed
Question:-
Option (A)
Zero
Option (B)
7700.8 N/m
Option (C)
15401.1 N/m
Option (D)
30803.4 N/m
Correct Option:
C
Question Solution:
Vertical forces = weight of fluid corresponding to semi circular volume
= w(pR2L/2) = 9.81 x 1000 x (p x (2)2 / (4 x 2)) x 1
= rg (pR2L/2)
= 15401.1 N/m
Question:-
Option (A)
h3s2 - h1s1 + h2s3
Option (B)
h1s1 + h2s3 - h3s2
Option (C)
h3s1 - h1s2 + h2s3
Option (D)
h1s1 + h2s2 - h3s3
Correct Option:
A
Question Solution:
Staring from point A and writing manometric equation
(PA/W) + h1S1 - h2S3 - h3S2 = PB/W)
\ (PA/W) – (PB/W) = h2S3 - h1S1 + h3S2
Question:-
Option (A)
rwm/D2
Option (B)
rwD2/m
Option (C)
rwmD2
Option (D)
rwmD
Correct Option:
B
Question Solution:
Let Æ = raDbmcw
MoLoTo = [ML-3]a[L]b[ML-1T-1]c[T-1]
a+C = 0 ....(1)
-3a + b-c = 0 ....(2)
-c-1 = 0 ....(3)
Hence a = 1, b= 2 and c = -1
\ Æ = (rwD2/m)
Alternate solution: Check the dimensions individually
Question:-
Option (A)
Whenever the flow is supercritical
Option (B)
If the flow is controlled by a sluice gate
Option (C)
If the bed slope changes from hill to steep
Option (D)
If the bed slope changes from steep to hill
Correct Option:
A
Question Solution:
The hydraulic jump is defined as the sudden and turbulent passage of water from a supercritical state.