Question:-
A furnace wall is constructed as shown in the below figure. The interface temperature Ti will be

Option (A)
560°C
Option (B)
200°C
Option(C)
920°C
Option(D)
1120°C
Correct Option:
(C)
Question Solution:
q’ = q/A = [ΔT / {(b1/k1)+(b2/k2)}]
Since heat flux remain same across the wall
= [(1000° -40°)/{(0.3/3)+(0.3/0.3)}] = [960 / {(1/10)+1}] = [(1000-T)/(1/10)]
= T = 1000 – (960/11)
= T = 912.7°C
question-answer-faq-6060