Question:-
A heat engine receives 1000 kW of heat at a constant temperature of 285°C and rejects 492 kW of heat at 5°C. Consider the following thermodynamic cycles in this regard
1. Carnot cycle
2. reversible cycle
3. Irreversible cycle
Which of these cycles could possibly be executed by the engine?
Option (A)
1 alone
Option (B)
3 alone
Option(C)
1 and 2
Option(D)
None of 1, 2 and 3
Correct Option:
(C)
Question Solution:
hcarnot = 1 –(T2/T1)= 50.179 %
hengine = {(Q1-Q2)/Q1} = 50.8%
hengine ² hcarnot = hrev
question-answer-faq-6114