Question:-
A long helical spring having a spring stiffness of 12 kN/m and number of turns 20, breaks into two parts of the resultant spring will be
Option (A)
6 kN/m
Option (B)
12 kN/m
Option(C)
24 kN/m
Option(D)
30 kN/m
Correct Option:
(C)
Question Solution:
k = (Gd4/64R3n)
ka(1/n) Þ (k2/k1) = (n1/n2)
\ (k2/12)=(20/10)
\ k2 = 24 kN/m
question-answer-faq-3261