Question:-
Two identical springs labeled as 1 and 2 are arranged in series and subjected to force F as shown in the given figure.

Assume that each spring constant is K. The strain energy stored in spring 1 is :
Option (A)
F2/2K
Option (B)
F2/4K
Option(C)
F2/8K
Option(D)
F2/16K
Correct Option:
(C)
Question Solution:
Stain energy stored by system (U)
= (1/2)F x d = (1/2) x F x (F/2k) [d=(F/2k)]
U = F2 / 4k
Strain energy stored by spring ---1
= U / 2 = F2 / 8k
question-answer-faq-9348