Question:-
When there is a miss in both L1 cache and L2 cache, first a block is transferred from main memory to L2 cache, and then a block is transferred from L2 cache to L1 cache. What is the total time taken for these transfers?
Option (A)
222 nanoseconds
Option (B)
888 nanoseconds
Option(C)
902 nanoseconds
Option(D)
968 nanoseconds
Correct Option:
(A)
Question Solution:
When there is a miss in both L1, L2, It has to access in Main which takes 200 nanoseans, and 20 nanoseconds to transfer to L2 cache and 2 for L1 cache, Total = 200 + 20 + 2 = 222
question-answer-faq-2253