Question:-
Which one of the following statements applicable to a perfect gas will also be true for an irreversible process? (Symbols have the usual meanings)
Option (A)
dQ = du + pdv
Option (B)
dQ = Tds
Option(C)
Tds = du + pdv
Option(D)
None of the above
Correct Option:
(C)
Question Solution:
By applying steady flow energy equation for throttling process w = 0, Q =0
h1+(C21/2) = h2 + (C22/2)= h3 +(C23)
(Assume z1 = z2 = z3)
For gas
CpT1 +(C21/2) = CpT2 + (C22/2) = CpT3 +(C23/2)
C­T¯
Q = AV
1-2 : A­ C¯ T­
2-3 : A¯ C­ T¯
question-answer-faq-2804