Question:-
Permissible bending moment in a circular shaft under pure bending is M according to maximum principal stress theory of failure the permissible bending moment in the same shaft is
Option (A)
1/2 M
Option (B)
M
Option(C)
ÖM
Option(D)
2M
Correct Option:
(B)
Question Solution:
Max bending stress s1 = M
Min. bending stress s2 = O
\ Max shear stress = ((s1-s2)/2) = (M/2)
Now. According to maximum shear stress theory tmax = (sper/2)
sper = M
question-answer-faq-2929