Question:-
A plane wall of thickness 2L has a uniform volumetric heat source q* (W/m3). It is exposed to local ambient temperature T¥ at both the ends (x = ± L). The surface temperature ts of the wall under steady-state condition (where h and k have their usual meanings) is given by
Option (A)
Ts = T¥ + (q*L/h)
Option (B)
Ts = T¥ + (q*/2k)
Option(C)
Ts = T¥ + (q*L2 / h
Option(D)
Ts = T¥ + (q*L2 / 2k)
Correct Option:
(A)
Question Solution:
t – t¥ = (q*L2/2k)= [1-(x/L)2]+(q*L/h)
At x = L , t = ts
ts - t¥ = (q*L/h)
Þ ts = t¥ + (q*L/h)
question-answer-faq-6096