Question:-
A box contains 2 washers, 3 nuts and 4 bolts. Items are drawn from the box at random one at a time without replacement.
The probability of drawing 2 washers first followed by 3 nuts and subsequently the 4 bolts is
Option (A)
2/315
Option (B)
1/630
Option(C)
1/1260
Option(D)
1/2520
Correct Option:
(C)
Question Solution:
Given, (Washers /2) (Nuts /3)(Bolts /4) (Total /9)

The probability of drawing two washers from 9 objects is (1/9c2) = (1/36)

The probability of drawing 3 nuts out of remaining 7 objects is (1/ 7c3) = (1/35)

The probability of drawing 4 bolts out of remaining 4 bolts is 1.

Therefore required probability (1/ (36x35)) = (1/1260)
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