# Production and Industrial Engineering Question set 11

Production and Industrial Engineering Question set 11
Question:-
Option (A)
467 kW
Option (B)
347 kW
Option (C)
322 kW
Option (D)
394 kW
Correct Option:
B
Question Solution:
Given capacity of the plant
= 100 TR = 350 kW
Mass flow rate (m) = 10 kg/sec
Here inlet and outlet water temperature is given, it indirectly gives the heat rejected by the condenser
Heat rejected by the condenser
= increase in temperature of water
= m Cp ΔT
= 10 × 4.2 (41.12 - 30)
= 467.04 kW
Motor power = 120 kW
Hence actual refrigeration effect
= 467.04 - 120
= 347.04 kW.
Question:-
Option (A)
Catalyst
Option (B)
protective agent
Option (C)
filler material
Option (D)
heat generator
Correct Option:
B
Question:-
Option (A)
1 ton
Option (B)
5 ton
Option (C)
10 ton
Option (D)
100 ton
Correct Option:
A
Question Solution:
1 ton = 210 kJ/min
therefore, Required refrigeration capacity
= = 1 ton
Question:-
Option (A)
its temperature and quality increase
Option (B)
its temperature decrease but quality increase
Option (C)
its temperature increase but quality decrease
Option (D)
its temperature and quality decreases
Correct Option:
B
Question Solution:
For throtting process of steam the enthalpy remains constant.
Now drawing temperature enthalpy diagram

From A to C pressure decreases, enthalpy = constant
Temperature decreases and quality improves.