Question:-
A shear of 20mm (S=20mm) is now provided on the blade. Assuming force vs displacement curve to be trapezoidal, the maximum force (in kN) exerted is
Option (A)
5
Option (B)
10
Option(C)
20
Option(D)
40
Correct Option:
(B)
Question Solution:
Work Done = t x shear area x K.t

Where K= penetration =0.2; T= thickness= 5 mm

Shear area = (200+200)X5=2000 mm2

Therefore W = 100X2000X5X0.2 = 200000 N-mm = 200 J

Work Done with shear = FmaxX(Kt + I) = 200

Fmax = 200/(5x0.2+20) = 9.5 KN nearly 10KN
question-answer-faq-2389