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Signals system Electrical Engineering

Signals system Electrical Engineering
Question:-
Option (A)
an and bn ; n = 1, 2, 3,.... ∞
Option (B)
a0 and bn ; n = 1, 3, 5,.... ∞
Option (C)
bn ; n = 1, 3, 5,..... ∞
Option (D)
an ; n = 1, 3, 5,..... ∞
Correct Option:
C
Question Solution:
• The wave has halfwave symmetry. So all even harmonics and dc term will be zero.
Also f(t) = -f(t) -> odd function.
So only odd haromnics of sine term will present.
Question:-
Option (A)
periodic with period N
Option (B)
aperiodic
Option (C)
periodic with period (N - 1)
Option (D)
periodic with period (N + 1)
Correct Option:
A
Question Solution:
x2[n] is periodic with period N
therefore, x2[(n - k) + N] = x2[n - k]
f(n + N) =
=
= f(n)
Question:-
Option (A)
24
Option (B)
36
Option (C)
72
Option (D)
None of these
Correct Option:
C
Question Solution:
x[n] =
=
Sequence x[n] is sum of two periodic signals
Period of first signal, N1 = 24
Period of second signal, N2 = 36
therefore, Period of x[n] =
=
=
Question:-
Option (A)
Option (B)
Option (C)
Option (D)
Correct Option:
C
Question Solution:
Impulse response, h[n] = s[n] - s[n - 1]
= (0.5)n u[n] - (0.5)n-1 u[n - 1]
=