Question:-
A single cylinder, four-stroke I.C. engine rotating at 900 rpm has a crank length of 50 mm and a connecting rod length of 200 mm. if the effective reciprocating mass of the engine is 1.2 kg, what is the approximate magnitude of the maximum ‘shaking force’ created by the engine?
Option (A)
533 N
Option (B)
666 N
Option(C)
133 N
Option(D)
None of the above
Correct Option:
(B)
Question Solution:
Maximum shaking force
= mw2r {cosq + (cos 2q / n)}
[n = (l/r) = (200/50) = 4]
= 1.2 {(2p x 900) / 60}2 x 50 x 10-3 (1+(1/4))
(at q = 0°)
f = 666 N.
question-answer-faq-6357