Question:-
In a small engineering project, for an activity the optimistic time is 2 minutes, the most likely time is 5 minutes and the pessimistic time is 8 minutes. What is the expected time of the activity?
Option (A)
1 minutes
Option (B)
5 minutes
Option(C)
8 minutes
Option(D)
18 minutes
Correct Option:
(B)
Question Solution:
te = {(t0+4tm+tp)/6}
= {(2+(4 x 5)+ 8) / 6}
= {(2+20+8) / 6} = 5 mins.
question-answer-faq-8846