SOM - Strength of Materials
SOM - Strength of Materials
Question:-
Option (A)
10 MPa, 100 MPa
Option (B)
100 MPa, 10 MPa
Option (C)
20 MPa, 200 MPa
Option (D)
200 MPa, 20 MPa
Correct Option:
A
Question Solution:
Δ=Δ_{1} + Δ_{2} => 0=_{} => 0=3P_{1} + 0.3P_{1} - 64.8 _{} _{}=> 64.8=3.3 P_{1} => P_{1}=19.64 kN therefore, P_{1} + P_{2}=216 therefore, P_{2}=216 - 19.64 = 196.36 kN therefore, Stress in region (1), σ_{1}_{}=_{} = 10 MPa and stress in region (2), σ_{2}=_{}
Question:-
Option (A)
_{}
Option (B)
2τ sin45°
Option (C)
2τ sin45° cos45°
Option (D)
_{}
Correct Option:
C
Question:-
Option (A)
span of beam is increased
Option (B)
moment of inertia is increased
Option (C)
select a material which is having less value of modulus of elasticity
Option (D)
increase the magnitude of load
Correct Option:
B
Question Solution:
_{}=M(x) y=_{} y∝_{}
Question:-
Option (A)
75%
Option (B)
99%
Option (C)
94%
Option (D)
90%
Correct Option:
C
Question Solution:
A P_{e}=_{} ^{}_{} = _{} =_{}= _{}= (0.5)^{4} therefore, % loss = _{} =[1 - (0.5)^{4}] x 100 =93.75 ~ 94%