TL Input Impedance Time Average Power Return and Insertion Losses. VSWR.
Example N4.1: Determine an expression for the voltage at the input to the TL assuming Rs = Z0:
To calculate the input voltage Vg , we’ll first determine the effective impedance seen at the TL input terminals seen looking towards the load at z = 0. This is called the input impedance Zin Forming the ratio of (19) and (20) from the previous lecture gives
. In other words, the input impedance is purely reactive
Z in = jX in where X in = - Z0 cot ( b l )
A plot of this reactance is shown in Fig. 2.8c of the text. An equivalent circuit can now be constructed at the input to the TL by using Rs and Zin as
Using voltage division,
This circuit voltage Vg is also the voltage on the TL at z = - l . That is, from (19) in the previous lecture
V( z = - l ) = 2V0+ cos (- Bl)
Since Vg = V( z = ?l) , we can equate these two voltages giving
More often than not, expressions of this type are used to determine V0+ in terms of Vs and Rs . We’ll see more on this topic in
Input Impedance of a Transmission Line
In problems like the one in the last example, it is helpful to have an analytical expression for the input impedance of an arbitrarily terminated TL. As we saw in the last lecture, the voltage and current everywhere on a homogeneous TL are
V(z) = V0+ e - jBz + V0- e + jBz
We can readily construct an input impedance expression for a TL of length l by dividing (1) and (2) for some arbitrary load reflection coefficient TL at z = 0:
Substituting for TL and simplifying gives
This is the input impedance for a lossless TL of length l and characteristic impedance Z0 with an arbitrary load ZL Three special cases are:
1. With an open circuit load ( ZL = ?), (5) yields
Zin = - jZ0cot (Bl ) beta
as we derived in the last lecture.
2. With a short circuit load ( ZL =0 ), (5) yields
Zin = jZ0 tan (b l) beta
A plot of this input reactance is shown in Fig. 2.6c.
3. With the resistive load ZL = Z0 , (5) yields
Zin = Z 0 beta
The input impedance is Z0 regardless of the length of the TL. All of these last three expressions should be committed to memory. You will use them often in microwave circuits. Note that both input impedances (6) and (7) are purely reactive, which is expected since neither type can dissipate energy, assuming lossless TLs.
Time Average Power Flow on TLs
A hugely important part of microwave engineering is delivering signal power to a load. Examples include efficiently delivering power from a source to an antenna, or maximizing the power delivered from a filter to an amplifier. Often, the “power” we are ultimately concerned with is the time average power PAv, expressed as
This expression is similar to that used in circuit analysis. Substituting V(z) and I(z) from (1) and (2) into (8) gives
Notice that the second and third terms are conjugates so that
The real part of this sum is zero. Consequently, (9) simplifies to
Since this power is not a function of z (true for a lossless and homogeneous TL), a z-dependence is no longer indicated for PAv. It is important to reiterate that we’re assuming a lossless TL throughout this analysis. These results are not valid for lossy TLs.Equation (10) is very illuminating. It shows that the total time average power delivered to a load is equal to the incident time The relative reflected time average power from an arbitrary load on a lossless TL is the ratio of the two terms in From (10) we see that if the load is entirely reactive so that , then PAv = 0 and no time average power is delivered to the load, as expected. For all other passive loads, PAv > 0. The time average power that is not delivered to the load can be considered a “loss” since the signal from the generator was intended to be completely transported – not returned to the generator. This return loss (RL) is defined as
RL =- 10log 10 (|TL|2) = -20log 10(|TL|) dB
The two extremes for return loss with a passive load are:
1. A matched load where TL =0 and RL = ? (no reflected power), and
2. A reactive load where TL =1 and RL = 0 (all power reflected).
Transmission Coefficient and Insertion Loss
Insertion loss is a term closely related to return loss. Consider a junction of two semi-infinite TLs as shown in Fig. 2.9:
We’ll arbitrarily assume that a voltage wave is incident from z < 0. From (1), the total voltages in the two regions are:
In these expressions,V0+ is the complex amplitude of the incident voltage wave and V1+ is the complex amplitude of the transmitted voltage wave. There is no reflection on the righthand TL so there is only the outgoing term. We will define the voltage transmission coefficient T as
so that (13) can be written as
At the junction of these TLs, the two boundary conditions are that the voltage and current are each continuous across the junction. Equating voltages (12) and (15) at z = 0 gives
The reflection coefficient for this junction of two TLs is
Substituting (17) into (16) and simplifying gives
This transmission coefficient between two “ports” in a microwave circuit is often expressed in decibels as the insertion loss, IL:
IL =- 10log10(|T|2) = - 20log 10 (|T|) dB
The two extremes for insertion loss in a passive circuit are: 1. A matched junction where ? = 0, so that T =1 and IL = 0 (all power transmitted), and
2. A completely reflecting junction where ? = ?1, so that T = 0 and IL = ? (no power transmitted).
Voltage Standing Wave Ratio
As we’ve seen, there is generally some amount of reflection of voltage and current waves from discontinuities and loads attached to a TL. To help quantify the amount of interference that exists on a TL, we define the voltage standing wave ratio (VSWR) as
where |V(z)|max and |V(z)|min are the maximum and minimum voltage magnitudes, respectively, found anywhere on a long TL. As shown in the text, we can determine expressions for these quantities. Specifically,
Substituting these into the definition of VSWR in (20) gives
From this expression, we can definitely see that VSWR is intimately related to the amount of reflection at the load (through ) and the subsequent interference on the TL.
Example N4.2: Compute the VSWR and return loss for the TL shown below. Plot the magnitude of the phasor voltage from z = 0 to z = -7 cm. From this plot, confirm the value of VSWR that you computed earlier.